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Radwanska extends winning streak to 10 matches with 1st-round victory at Australian Open

The Associated Press / Times Colonist
January 13, 2013

Slovakia's Dominika Cibulkova returns a shot to Poland's Agnieszka Radwanska during the women's final of the Sydney International tennis tournament in Sydney, Australia, Friday, Jan. 11, 2013. Radwanska won the match 6-0, 6-0. (AP Photo/Rob Griffith)

MELBOURNE, Australia - Agnieszka Radwanska has won her 10th consecutive match of 2013, defeating Australian wildcard entry Bojana Bobusic of 7-5, 6-0 in the first round at the Australian Open on Monday.

The No. 4 -seeded Radwanska captured the Sydney International title on Saturday, beating Dominika Cibulkova of Slovakia 6-0, 6-0 a week after winning a WTA tournament in Auckland, New Zealand. The 23-year-old Radswanska has 12 career singles titles.

Bobusic was serving for the first set at 5-4, but Radwanska break in that game and again in the 12th to take the first set and start a dominating roll in the second.

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